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notify/grove: set the service to "ansible" by default

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zimbatm
2014-01-21 12:43:25 +00:00
parent 4b9127f0af
commit fe4d203b9a
1 changed files with 4 additions and 3 deletions
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7
library/notification/grove
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@@ -16,8 +16,9 @@ options:
required: true
service:
description:
- Name of the service (displayed in the message)
required: true
- Name of the service (displayed as the "user" in the message)
required: false
default: ansible
message:
description:
- Message content
@@ -66,7 +67,7 @@ def main():
argument_spec = dict(
channel_token = dict(type='str', required=True),
message = dict(type='str', required=True),
service = dict(type='str', required=True),
service = dict(type='str', default='ansible'),
url = dict(type='str', default=None),
icon_url = dict(type='str', default=None),
)